Transforming a 3-D array into a 2-D by sorting by the 2nd layer, then removing zeros

I have made a 3-D array by iterating through 3 loops where the number of occurances in the last loop is different for each loop1/loop2.The result is a 50x10x18 array where 18 is the max value of occurances during loop 3 and if there are less occurances there will be unwanted zeros at the end of the 3rd loop (see example below)

length of loop1 = 50

length of loop2 = 10

length of loop3 = 18

example:

array(1,1, :) = [1 4 6 2 4 0 0 0 0 0 0 0 0 0 0 0 0 0]

array(2,1, :) = [2 5 1 2 5 2 4 2 0 0 0 0 0 0 0 0 0 0]

Is there a way to iterate through the first loop (loop1) and concatenate all values from loop 3, sorted by loop 2 and then remove zero values?

I would like to end up with a 10x(18*50) array, where it is sorted by the 2nd loop then remove zeros.

for example the beginning of the first column in the 10x(18*50) array would be [1 4 6 2 4 0 0 0 0 0 0 0 0 0 0 0 0 0 2 5 1 2 5 2 4 2 0 0 0 0 0 0 0 0 0 0 ...]

then ideally after concatenation I would remove the zero values and the beginning of the first column in the array would be: [1 4 6 2 4 2 5 1 2 5 2 4 2 ...]