Is my code of rayleigh fading right?

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yang-En Hsiao
yang-En Hsiao on 2 Oct 2019
Is my code of rayleigh fading right?
H_A=1/sqrt(2)*[randn(2,6) + i*randn(2,6)];
Because it seems that i just create a AWGN channel in the real part,and create a AWGN channel in the imaginary part,then combine and normalize it.
So H_A is a 2 by 6 matrix

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