Clear Filters
Clear Filters

For loops and taylor series

9 views (last 30 days)
SonOfAFather on 6 Sep 2012
Commented: Dillan Masellas on 8 Apr 2016
I am having issued with my for loop taking the variable that i have set to be [1:1:n] but when i run my script it turns my answer into a scular in stead of a matrix.
here is what i have any help would be great thanks.
close all;
n = input('Please give number for the total number of terms in the taylor series: ');
x = input('Please give a value for "x": ');
approxValue = 0;
% Initial value of approxValue.
for k = [0:1:n];
approxVakue = (approxValue + k);
approxValue = sum(x.^k/factorial(k));
% Gives the approx value of e^x as a taylor series
disp('approxValue =')
disp('e^x =')
  1 Comment
Dillan Masellas
Dillan Masellas on 8 Apr 2016
How can I perform this operation without using the power function?

Sign in to comment.

Accepted Answer

Matt Fig
Matt Fig on 6 Sep 2012
Edited: Matt Fig on 6 Sep 2012
Use this loop instead:
for k = 0:n
approxValue = (approxValue + x.^k/factorial(k));
% Gives the approx value of e^x as a taylor series
I don't know what approxVakue is supposed to be doing in your code??
And what do you expect to be a matrix? Are you trying to save each term? If so:
approxValue = zeros(1,n+1);
for k = 0:n
approxValue(k+1) = x.^k/factorial(k);
approxValuesum = sum(approxValue); % Holds the estimate
This could also be done without FOR loops...
SonOfAFather on 6 Sep 2012
thank you i understand now. It wasn't that i needed to know that the value of k it was that it didn't do what i thought it would do. i thought that the value of k would still stay in vector form, but your explaination corrected my thought process. thank you.
SonOfAFather on 12 Sep 2012
In the end i was told that"n" should have been "n-1" in
for k = 0:n should have read k = 0:n.
the explaination i was given was that each time to loop processed through it needed to be one less.
thanks for you help. just thought i would tell you how i was corrected.

Sign in to comment.

More Answers (0)


Find more on Loops and Conditional Statements in Help Center and File Exchange


Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!