Info
This question is closed. Reopen it to edit or answer.
Optimization constraint not met
1 view (last 30 days)
Show older comments
Hey
New to matlab and trying to model a hot water storage tank that buys electricity when the price is low and uses it later to meet the demand. So in a perfect scenario 100% of the demand would be stored or purchased when the cost is low. The heater can produce Q_hph, which can either be sent to meet demand Q_hphj or it can be sent to the tank Q_teshin. Q_hph can be greater than the demand (Q_demh) but Q_demh==Q_hphj+Q_teshout, where Q_teshout is what leaves the tank.
When I run the optimization, Q_hph always returns 0 and Q_teshout=Q_demh, which shouldn't be the case without first having a value for Q_teshin.
Thanks in advance for any help!
Michael
2 Comments
Sahithi Kanumarlapudi
on 8 Aug 2019
In the code which you have provided you did not declare the variable ‘i’. Provide the correct declaration.
Answers (0)
See Also
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!