How to generate a random point in the volume of a cylinder

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I have a cylinder in three-dimensions with a long-axis defined by the endpoints ?1 and ?2, and radius ?. p1=[0.5, 0.3, 1]; p2=[0.4, 0.5, 0.7]; R=0.5;
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James Tursa
James Tursa on 24 Jun 2019
What have you done so far? What specific problems are you having with your code? Do you know how to generate a random point inside a circle? Do you know how to rotate vectors in 3D space?

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Accepted Answer

John D'Errico
John D'Errico on 24 Jun 2019
Since you already have an answer posted... Pretty easy, actually. So two points that define the ends of the cylinder, and a known radius.
p1=[0.5, 0.3, 1];
p2=[0.4, 0.5, 0.7];
R=0.5;
N = 100000; % # of points to generate
First, generate a random point along the cylinder axis. The vector that defines the axis is given by:
axialvec = p2 - p1;
axialvec = axialvec/norm(axialvec);
axialpoints = p1 + (p2 - p1).*rand(N,1);
Next, we work in a cylindrical coordinate system around the centerline. Generate points at random inside a circle of radius R, in TWO dimensions.
circr = sqrt(rand(N,1))*R;
circtheta = rand(N,1)*2*pi;
circpoints = [cos(circtheta).*circr,sin(circtheta).*circr];
Rotate the points into the plane perpendicular to the axis.
axnull = null(axialvec);
points = axialpoints + circpoints*axnull.';
And plot.
plot3(points(:,1),points(:,2),points(:,3),'.')
grid on
box on
axis equal
Rotate it around to convince yourself the points form a cylinder.
untitled.jpg

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