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surendra kumar Aralapura mariyappa
on 13 Jun 2019

Commented: surendra kumar Aralapura mariyappa
on 15 Jun 2019

Hey all,

I know what I am asking is wrong, but I have to slove it at any cost.

I have sOme materials .1 2 3 4 5 6 7 8 9 10;

Now 1 and 2 are in series 1--2

2 and 3 are in series 2--3

3 and 4 are in series 3 --4

1 and 5 are in parallel =

8 and 5 are in series 8-5

8 and 6 are in parallel =

6 and 7 are in series 6-7

5 and 9 are in Series 5 - 9

9 and 10 are in series 9 -10

9 are 2 are in parallel =

10 and 3 are in parallel =

Now I need to build separate function file to let the slover knows which one is in parallel or series with other element.

My code is like this:

classdef Connection

enumeration

Series, Parallel

end

end

function [C] = find_Connection(i)

[Lambda, A, B, D, M, A1,M_S, M_P] = Matrix_surendra13; %% this is the input file which %contains the input arguments.

C = 0;

% M_S is a row vector which contains materials in Series . M_S = [ 1 2 3 4 5 8 6 7 9 10];

%M_P is a row vector which contains materials in parallel M_P = [ 1 5 7 9 10];

if (find(M_S == i))

C = Connection.Series;

elseif (find(M_P == i))

C = Connection.Parallel;

end

function Slover

[Lambda, A, B, D, M, A1,M_S, M_P] = Matrix_surendra13; % ignore this called function it is just an %input argument file

for i = 1:Size(A,1) % A from the input argument file square matrix always

for j = 1:size(A,2)

C1 = find_Connection(i);

C2 = find_Connection(j);

if (C1 == Connection.Series && C2 == Connection.Series)

LA = A(i,j)*B(i)*D(j)*Lambda(j);

elseif (C1 ==Connection.Parallel && C2 == Connection.Parallel)

LB = A(i,j)*Lambda(i)*Lambda(j);

end

So the problem is each material has two possiblities either Series or Parallel with others. If I use my code it doesn't work.

For an example,

i = 1; j = 1;

Material 1 is in Series with 2 and in Parallel with 5, when the solver enter the function file find_Connection(i) it will automatically take Series statement since first condition will be fulfilled. This is fine for 1 and 2. LA will be computed.

But when i = 1 and j = 5; in parallel

slover sholud take LB, but it will compute LB bcoz both i = 1 and i = 5 are there in series vector file as well as in parallel vector file, so first condtion in the find_Connection file will be fulfuilled, so solver will not check second one.

I think that I gave the proper explanation.

Kindly as for the more detail if it is not clear.

any suggestions and answers are most welcomed.

Thanks in Advance.

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