invalid syntax at '=' . A '(' might be missing a closing ')'
2 views (last 30 days)
Show older comments
valerio auricchio
on 29 Mar 2019
Commented: Guillaume
on 29 Mar 2019
The error is at line 14 and 26
switch nargin
case 0
disp('Non ci sono stati input per la funzione!')
case 1
if (f = 0)
disp('Non hai inserito correttamente la funzione la funzione')
end
case 2
if(~isscalar(xo) || isinteger(xo))
disp('Mammt')
end
case 3
if(~isscalar(xo) || isinteger(xo)) % anche se ci sta un altro controllo che nello non vuole dirmi
disp('A')
end
case 4
if(~isinteger(NMAX) || NMAX = 0 || ischar(NMAX))
disp('A pecrrrr, cioè nmax non va bene')
end
end
0 Comments
Accepted Answer
Catalytic
on 29 Mar 2019
Edited: Catalytic
on 29 Mar 2019
if (f == 0)
and same thing in this line
if(~isinteger(NMAX) || NMAX == 0 || ischar(NMAX))
1 Comment
Guillaume
on 29 Mar 2019
Note that matlab is not C, there is no need to enclose a conditional statement in (), so
if f == 0
if ~isinteger(NMAX) || NMAX == 0 || ischar(NMAX)
Note that isinteger check that the type is integer not that the values are integer,
>> isinteger(1) %return false, since double is not an integer type
ans =
logical
0
>> isinteger(uint8(1)) %return true, the type is integer
ans =
logical
1
I suspect that you meant to test if the value was integer, not the type.
Also note that the ischar(NMAX) is redundant, if NMAX is char, it will have failed the ~isinteger test.
validateattributes(f, {'numeric'}, {'nonzero', 'scalar'});
validateattributes(NMAX, {'numeric'}, {'integer', 'nonzero', 'scalar'})
More Answers (0)
See Also
Categories
Find more on Measurements and Spatial Audio in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!