Interpolating a 3D matrix
7 views (last 30 days)
Show older comments
I have a 14x14x221 matrix, A. Using a loop over the third dimension, I'm trying to interpolate the 14x14 matrix at each iteration of this loop to produce a new matrix that has more data points. Then save the new matrix at each iteration to form a new 3D matrix that has X,Y dimensions much greater than 14.
I have a script that does this for the rows but there is something wrong with the second nested for loop, which interpolates column-wise.
I keep getting this error "Unable to perform assignment because the size of the left side is 14-by-1 and the size of the right side is 1-by-221" for this line
NewestA(:,g,h) = R;
N = 221 ;
[m,n,p] = size(A) ;
NewA = zeros(m,N,p) ;
xi = linspace(1,n,N) ;
for i = 1:m % Splining row wise
for j = 1:p
T = interp1(1:n,A(i,:,j),xi) ;
NewA(i,:,j) = T ;
end
end
A = NewA ;
[m,n,p] = size(A) ;
NewestA = zeros(m,N,p) ;
yi = linspace(1,m,N);
for g = 1:n
for h =1:p
R=interp1(1:m,A(:,g,h),yi);
NewestA(:,g,h) = R;
end
end
A=NewestA
0 Comments
Answers (1)
Star Strider
on 26 Mar 2019
2 Comments
Star Strider
on 26 Mar 2019
I didn’t know this is homework.
My one suggestions is that with respect to the second loop, perhaps:
[m,n,p] = size(NewA) ;
might be more appropriate.
See Also
Categories
Find more on Interpolation in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!