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Cant get the equation to work
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clc
num_values=11;
first_val=0;
time=zeros(1,num_values);
z(1)=first_val;
s=zeros(1,11);
time(1)=first_val;
t=sym('t');
TU(1)=5*pi/180;
TU(2)=7*pi/180;
TU(3)=6*pi/180;
TU(4)=9*pi/180;
TU(5)=12*pi/180;
TU(6)=17*pi/180;
TU(7)=19*pi/180;
TU(8)=27*pi/180;
TU(9)=33*pi/180;
TU(10)=36*pi/180;
TU(11)=45*pi/180;
for n=2:11
time(n)=(n-1)*15;
z(n)=(-z(n-1)+((2*(TU(n)-TU(n-1)))/(time(n)-time(n-1))));
sprintf('z= %.05f \n',z)
end
for n=2:10;
s(n)=((z(n)-z(n-1))/(2*(time(n)-time(n-1)))) * ((t-time(n-1)).^2) + z(n-1)*(t-time(n-1))+TU(n-1);
end
Im trying to get the values from the equation with s using the values of the equation with z and i dont know how. In the workspaces it says that s is a 1x11 matrix but i think it should be 1x10
4 Comments
Jan
on 28 Nov 2018
"it says" - who is it? Please post the complete error message, such that the readers do not have to guess, which line fails with which message.
Answers (1)
Areej Varamban Kallan
on 7 Dec 2018
Edited: Areej Varamban Kallan
on 7 Dec 2018
Hi Clara,
I have executed your code and the error message I get is "Unable to convert expression into double array". The variable 's' is defined to be a double matrix and the variable 't' is defined to be a symbolic variable. In the second for loop you are doing certain computations using the symbolic variable 't'. The results of such computations will be of symbolic type. As a result your code is attempting to assign a symbolic value to a double matrix. This is not valid.
Please redine s as:
s=sym(zeros(1,11));
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