Clear Filters
Clear Filters

find the average of a vector with specific condition ?

2 views (last 30 days)
I had A vector
A=[1 0 0 2 3 2 3 5 0 0 0 0 1 2 1 0 0 0 0 3 4 0 0 0 0 0 0 1 2 3 2 0 0 0 0 2 0 0]
like this. Now I want a vector B having average of corresponding non-zero value, like
B(1)=average(A(1));
B(4)=average(A(4):A(8));
B(13)=average(A(13):A(15);
B(20)=average(A(20):A(21));
B(28)=average(A(28):A(31)) and so on .....rest values should be zeros.
hence
B=[1 0 0 3 0 0 0 0 0 0 0 0 1.33 0 0 0 0 0 0 3.5 0 0 0 0 0 0 0 2 0 0 0 0 0 0 0 2 0 0 ]
  5 Comments
MUKESH KUMAR
MUKESH KUMAR on 4 Sep 2018
So how can i take average of continuous values at starting point of each continuous group values and rest are zeros.
jonas
jonas on 4 Sep 2018
I'll give it a try in an hour if no one gave you an answer. This one is not as straight-forward as your previous questions, at least to me.

Sign in to comment.

Accepted Answer

jonas
jonas on 4 Sep 2018
Edited: jonas on 4 Sep 2018
Credits to Guillaume for cleaning up my original code.
A=[1 0 0 2 3 2 3 5 0 0 0 0 1 2 1 0 0 0 0 3 4 0 0 0 0 0 0 1 2 3 2 0 0 0 0 2 0 0];
B=zeros(size(A));
bounds = find(diff([0, A, 0] ~= 0));
starts = bounds(1:2:end);
ends = bounds(2:2:end) - 1;
B(starts) = arrayfun(@(s, e) mean(A(s:e)), starts, ends);
  4 Comments
jonas
jonas on 4 Sep 2018
@Guillaume: Thank you sir, I'll update the code.
@Mukesh: The code should work now. There was a minor error in my original post. You were too quick to grab it :)

Sign in to comment.

More Answers (0)

Categories

Find more on Data Types in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!