How to take first element from the cell?
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Dear all,
I have a cell
d={[3,80,32,13] [3,80,17] [3,45,18] [3,45,20] [3,80,32] [3,45] [3,80,47] [3,45,93,62] [3,80] [3,45,93]}
Also I have vector c= [80 45];
The question is : How to take the first element that locate it after vector c numbers ?
The expected result is =
{[32] [17] [18] [20] [32] [] [47] [93] [] [93]}
Also I would like to get other elements that locate it after the first element in another cell, for example:
x = {[13] [] [] [] [] [] [62] [] []}
please help>>>>
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Answers (1)
Stephen23
on 29 Jul 2018
Edited: Stephen23
on 29 Jul 2018
Something like this (untested, but should get you started):
N = numel(d);
R = cell(1,N);
X = cell(1,N);
for k = 1:N
idx = ismember(d{k},[80,45]);
idx = [false,idx(1:end-1)];
if any(idx)
R{k} = d{k}(find(idx,1,'first'));
end
idx = [false,idx(1:end-1)];
if any(idx)
X{k} = d{k}(find(idx,1,'first'));
end
end
2 Comments
Stephen23
on 30 Jul 2018
@laith Farhan: I hope that it helped. Remember to accept the answer that helped you most: accepting answers is the easiest way to show your appreciation to the volunteers who help you on this forum.
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