Find the number of times a number is in an array for every column

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NMans
NMans on 21 Jun 2018
Answered: Fangjun Jiang on 21 Jun 2018
Hi, this is probably quite simple but can't get my head around it. I have 8784 x 9 matrix and I want to find value <= 0 in this matrix for each column and save the answer as a new matrix of 1 x 9. I've started with this:
[nrow, ncol] = size (matrix)
for k = 1:ncol
newMatrix = find(matrix =>0)
end
This ends up giving me just 1 column instead of 9 columns. Eventually I want to use the number of times the value of 0 (or less) occurs in each column as part of my next calculation. Can anybody help? Thanks!

Accepted Answer

Fangjun Jiang
Fangjun Jiang on 21 Jun 2018
Hope this give you a clue
a=rand(3,9)-0.5;
b=a<=0;
c=sum(b)

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