Plot points with unknown column numbers

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Hello
I am trying to plot points with unknown column numbers for instance: plot (fx,fy,'bo',ax(i,1),ay(i,1),'bo',ax(i,2),ay(i,2),'bo')
where fx and fy are not changing, however ay and ax will plot according the row and column number all on the same time. However, every time I will be getting n columns ranging from 1 to depends. I tried hold on but the points from the previous plot are there, in which i dont want.
is there a way that i can automate this code to generate a line as the code above with different column numbers every time ?
here is the full code figure(2) names = 1:1:rx; for i =1:1:rx name = i; plot (fx,fy,'bo',ax(i,1),ay(i,1),'bo',ax(i,2),ay(i,2),'bo') xlim([0 50]); ylim([0 50]); title(sprintf('%s Step: %i',sys,i)); pause (0.5) end
Thanks

Accepted Answer

Kevin Holst
Kevin Holst on 5 Jun 2012
Here's the fix, sorry it took a while. Got distracted ;)
figure(2)
names = 1:1:rx;
for i =1:1:rx
name = i;
plot (fx,fy,'bo')
xlim([0 50]);
ylim([0 50]);
hold on
for j = 1:scell
plot(ax(i,j),ay(i,j),'bo')
end
title(sprintf('%s Step: %i',sys,i));
pause (0.35)
hold off
end

More Answers (2)

Kevin Holst
Kevin Holst on 5 Jun 2012
did you turn hold back off?
figure(2)
names = 1:1:rx;
for i =1:1:rx
name = i;
plot (fx,fy,'bo')
xlim([0 50]);
ylim([0 50]);
hold on
for j = 1:size(ax,2)
plot(ax(i,j),ay(i,j),'bo')
title(sprintf('%s Step: %i',sys,i));
pause (0.5)
end
hold off
end
  3 Comments
Kevin Holst
Kevin Holst on 5 Jun 2012
Let me see if I have this correct... you have 2 vectors fx,fy that are not changing and they should be there at all times. Then you have two matrices ax, ay where the rows are different cases (presumably) and the columns are different timesteps? So the first plot should be fx,fy and one point at ax(1,1),ay(1,1). The plot should then wait 0.5 seconds and then plot the second point on the axes at ax(1,2),ay(1,2), along with the first point and fx,fy. Is that right? If that's the case, then I think I've updated the code to do that... also your title should probably change with every column step right? if that's the case, then you'll need to change the i in your tltle call to a j.
Avni
Avni on 5 Jun 2012
not quite, i emailed you the code along with the data, so it may be easier to understand the difference between my plot code and yours!

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Avni
Avni on 5 Jun 2012
sorry the code came out funky
figure(2)
names = 1:1:rx;
for i =1:1:rx
name = i;
plot (fx,fy,'bo',ax(i,1),ay(i,1),'bo',ax(i,2),ay(i,2),'bo')
xlim([0 50]);
ylim([0 50]);
title(sprintf('%s Step: %i',sys,i));
pause (0.35)
end

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