How to create a perimeter from x,y coordinates
Show older comments
Hello everybody,
I have a small question:
I have two matrices: A(2099x2) and B(9x4).
Matrix A = trajectory (x,y)
Matrix B = X,Y position of 9 (black square dots), the width=0.20 and the height= 0.20.
I would like to know how to create a perimeter around of the black square dots (green square) and calculate if the trajectory (blue line) enter in this perimeter. Thanks in advance

Answers (1)
Guillaume
on 20 Mar 2018
The easiest way, assuming R2017b or later, is to use the intersect method of the polyshape object, which you can construct either by providing the 4 corners of your perimeter or with nsidedpoly:
perimeterside = 0.2;
for blackdotidx = 1:size(B, 1) %iterate over the black dots
perimeter = nsidedpoly(4, 'Center', A(blackdotidx, :), 'SideLength', perimeterside);
if ~isempty(intersect(perimeter, A))
%1st output of intersect is segments inside the perimeter, so if not empty there is intersection
fprintf('trajectory intersect perimeter %d\n', blackdotidx);
end
end
5 Comments
Alex castilla
on 21 Mar 2018
Edited: Alex castilla
on 21 Mar 2018
Guillaume
on 22 Mar 2018
"I don't have the earlier version of Matlab" Do you mean you're not on R2017b or R2018a or that you are?
If you are, then you can use the code that I wrote. I don't see what your code has anything to do with it.
Alex castilla
on 22 Mar 2018
Edited: Alex castilla
on 22 Mar 2018
Guillaume
on 22 Mar 2018
Matlab online is always on the last version. The code I wrote does not require any particular toolbox so is guaranteed to work with matlab online.
I understood very well what you want to do, my answer does just that.
Alex castilla
on 22 Mar 2018
Categories
Find more on Polygonal Shapes in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!