Generating the Ulam Spiral

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Prince
Prince on 30 Apr 2012
This short spiral(n) function is supposed to generate a number spiral centered at one. For the most part, I understand the code but I can't seem to grasp why the polynomial m^2-m+1 is used.
function S = spiral(n)
%SPIRAL SPIRAL(n) is an n-by-n matrix with elements
% 1:n^2 arranged in a rectangular spiral pattern.
S = [];
for m = 1:n
S = rot90(S,2);
S(m,m) = 0;
p = m^2-m+1;
v = (m-1:-1:0);
S(:,m) = p-v';
S(m,:) = p+v;
end
if mod(n,2)==1
S = rot90(S,2);
end
Any ideas?

Accepted Answer

Prince
Prince on 30 Apr 2012
Figured it out... the quadratic designates the values along the main diagonal.
For any future searchers

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