Function for day of the year
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amateurintraining
on 11 Oct 2017
Edited: per isakson
on 11 Oct 2017
How do I write a function that responds the days of the year when given a certain date? For example, January 7th, 2017 would respond 7 as that is the 7th day of the year. (This is also accounting for leap years.)
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Accepted Answer
per isakson
on 11 Oct 2017
Edited: per isakson
on 11 Oct 2017
Introduced in R2014b
>> day( datetime('07-Jan-2017', 'InputFormat', 'dd-MMM-yyyy' ), 'dayofyear' )
ans =
7
"accounting for leap years" If not, shame on The MathWorks!
>> day( datetime('01-Mar-2017', 'InputFormat', 'dd-MMM-yyyy' ), 'dayofyear' )
ans =
60
>> day( datetime('01-Mar-2016', 'InputFormat', 'dd-MMM-yyyy' ), 'dayofyear' )
ans =
61
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