# creating matrix w.r.t. rows number of another matrix

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data=[1;2;8;9;11;12;19;22;24;26;30];

col_row=[1 2;1 4;1 8;1 11;2 4;2 8;2 11;3 10];

rows number in col_row are always ascending order. I need to store result_i matrix w.r.t. data and rows value of col_row matrix as follows.

result_1=[data(2);data(4);data(8);data(11)];

result_2=[data(4);data(8);data(11)];

result_3=data(10);

rows number in col_row always starts with 1. I need to extract second column values of each repeated numbers (1-2) and single number in col_row matrix and create result_i matrix.

Above data is example, actual data matrix is bigger and the maximum row value of col_row matrix is variable. How can I write a code to store result_i matrix?

##### 2 Comments

James Tursa
on 6 Sep 2017

Stephen23
on 7 Sep 2017

"I need to ... and create result_i matrix"

Do not do this. It will make your code complex, slow, buggy, hard to debug, and obfuscated. Read this to know why creating or accessing variable names dynamically is a bad idea:

Indexing is simple, efficient, neat, easy to debug, and easy to understand: you should use indexing with some kind of array: a matrix, or an ND array, or a cell array, or a structure, or a table, or....

### Accepted Answer

James Tursa
on 6 Sep 2017

Edited: James Tursa
on 6 Sep 2017

E.g., a method using a cell array

u = unique(col_row(:,1));

n = numel(u);

result = cell(max(u),1);

for k=1:n

result{u(k)} = data(col_row(col_row(:,1)==u(k),2));

end

This assumes that all of the "row" numbers are positive integers. If they are not, then one could do this instead

u = unique(col_row(:,1));

n = numel(u);

result = cell(n,1);

for k=1:n

result{k} = data(col_row(col_row(:,1)==u(k),2));

end

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