# how to find the equivalent resistance of two resistors in parallel and series

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Kartickeyan V on 18 Jul 2017
Edited: Andrei Bobrov on 18 Jul 2017
help me finding the equivalent resistance of two resistors for example r1 and r2 in parallel and series
clc;
clear all;
r1=1200;
r2=1000;
rt=parallel(r1,r2);
display('rt')
when i run this code i am getting either answer ams as 1 or some error
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Stephen23 on 18 Jul 2017
What is parallel ?

dbmn on 18 Jul 2017
parallel might not be the best function to use here. See more in the documentation (which is what you should do everytime you use a function either by typing help parallel or doc parallel)
sys = parallel(sys1,sys2)
% Which needs sys, sys1 and sys2 in a state space notation to work
but why bother writing these in that special state space notation when you can simply use Wikipedia and Google
rt = r1*r2 / (r1+r2);

Andrei Bobrov on 18 Jul 2017
Edited: Andrei Bobrov on 18 Jul 2017
r1=1200;
r2=1000;
parallel = @(r1,r2)1/sum(1./[r1,r2]); % or: parallel = @(r1,r2)prod([r1,r2])/sum([r1,r2]);
rt=parallel(r1,r2)