# Error Matrix dimensions must agree

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jack carter on 5 Jul 2017
Commented: jack carter on 6 Jul 2017
I am getting "Matrix dimensions must agree" error while running the following codings in MatLab. From the first two equations I am getting error because of exp(f.*phi) part. If I remove this part, the code works fine. But I need to add this in both equations. In the last equation I am getting error due to the factor_c part. Could someone help me correcting the mistakes? Thanks
function myfunction
n=0;Ef=40*10^6;df=0.014;rou=3*10^6;S=0:600;f=0.5;phi=0:0.01:pi/2;Le=2;Vf=0.02;
P_friction=(pi/2)*sqrt((1+n)*Ef*df^3*rou*S).*exp(f.*phi);
Pslip=pi*rou*Le*df*(1-S/Le)*exp(f.phi);
factor_a=(4*Vf/(pi*df^2));
factor_b=Pslip.*P_friction;
factor_c=p_phi*p_z;
sigmab=factor_a.*factor_b.*factor_c;
end

Star Strider on 5 Jul 2017
First, you need an operator here, I assume multiplication:
Pslip=pi*rou*Le*df*(1-S/Le)*exp(f.*phi);
↑ ← INSERT ‘*’ HERE
What are ‘p_phi’ and ‘p_z’ here:
factor_c=p_phi*p_z;
I do not see where you have defined them, and your function does not have any arguments. A function file will not pick up variables from your workspace as an anonymous function would.
Star Strider on 5 Jul 2017
If you want all the vectors to be the same lengths, you will have to define ‘z’ as:
z = bsxfun(@rdivide, [0:Lf]', 2*cos(phi));
p = 2*z/Lf;
This creates a (3x100) matrix for ‘p’.
You cannot use 0 as a subscript. In MATLAB, indexing begins with 1.

KSSV on 5 Jul 2017
Your S and phi should be arrays with equal dimensions. In your code they are not same. You need to proceed like below.
N = 100 ; % can be changed
n=0;
Ef=40*10^6;
df=0.014;
rou=3*10^6;
S = linspace(0,600,N) ;% S=0:600;
f=0.5;
phi = linspace(0,pi/2,N) ;% phi=0:0.01:pi/2;
Le=2;
Vf=0.02;
P_friction=(pi/2)*sqrt((1+n)*Ef*df^3*rou*S).*exp(f*phi);
Pslip=pi*rou*Le*df*(1-S/Le).*exp(f*phi);
jack carter on 6 Jul 2017