How to display images from a cell array?

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fiona rozario
fiona rozario on 31 May 2017
Commented: Image Analyst on 1 Jun 2017
I have 5 images in a cell array 'imageshares' and I want to display them individually.
figure
image(imageshares{i}));
I used the above code and obviously this didn't work. How do I display the images?
  4 Comments
fiona rozario
fiona rozario on 1 Jun 2017
f=imread('test2.jpg');
red=f(:,:,1);
green=f(:,:,2);
blue=f(:,:,3);
[r,c,d]=size(f);
shred=zeros(r,c);
shgreen=zeros(r,c);
shblue=zeros(r,c);
image=zeros(r,c);
N = input('Number of pieces to break into ');
rowgroups = diff( round(linspace(0,r,N+1)));
rshares = mat2cell(red, rowgroups, size(red,2));
gshares = mat2cell(green, rowgroups, size(green,2));
bshares = mat2cell(blue, rowgroups, size(blue,2));
imageshares=mat2cell(image, rowgroups, size(image,2));
shredshares = mat2cell(shred, rowgroups, size(shred,2));
shgreenshares = mat2cell(shgreen, rowgroups, size(shgreen,2));
shblueshares = mat2cell(shblue, rowgroups, size(shblue,2));
for i=1:N
imageshares{i}=cat(3,rshares{i},gshares{i},bshares{i});
figure
image(imageshares{i});
end

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Answers (2)

Star Strider
Star Strider on 31 May 2017
The subscript error is puzzling if ‘i=1:N’. One option is to change the loop counter variable to ‘k’ instead, since a few versions back, ‘i’ could default to the imaginary operator.
The imshow function could be a preferable option (with the index variable change):
figure
imshow(imageshares{k})
This is a guess on my part. If I guessed wrong, I will delete this Answer.
  1 Comment
fiona rozario
fiona rozario on 1 Jun 2017
I tried this but still got the same error.

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Image Analyst
Image Analyst on 1 Jun 2017
image is a built in function. Thus, this makes no sense:
imageshares=mat2cell(image, rowgroups, size(image,2));
and I don't know what you're doing with all that "shares" stuff. You read in one image, which has 3 color channels, so exactly what 5 images are you expecting to see?
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