check answer in range otherwise do again process with random generated number check until all digit of loop in range

for k1=1:10                      %set population generation limit her
    pop1h(k1)=randi([200 1150],1,1 );  %random genertor limit n*3 mean n-row and 3-three colum
end
pop=pop1h*2
  if pop<500;
   break
  else
      continue 
  end

[Pratik Anandpara]

pop1h generate 10 random number from 200 to 1150 now need to check this answer pop=pop1h*2 if this answer is<500 than not valid again new 10 digit generate and do same process untill condition satisfy

Answer 1

[KSSV]

for k1=1:100                     %set population generation limit her
    pop1h=randi([200 1150],1,1 );  %random genertor limit n*3 mean n-row and 3-three colum

      pop=pop1h*2 ;
      if pop<500;
          disp('condition satisfied loop exited') ;
          break
      else
          continue
      end
  end

[Pratik Anandpara]

generated answer is give pop<500 is not valid

[KSSV]

What? if the condition is satisfied, loop will break displaying condition is met. If not loop runs for given number.

[Pratik Anandpara]

pop<500 means condition is not satisfy pop>500 always i want

[KSSV]

You want to store pop>500 values?

[Pratik Anandpara]

loop break and want answer last 10 in range not stop from breakpoint

[Pratik Anandpara]

i want final answer in 10 digit array after put value in equation POP=POP1H*2... and all 10 digit follow --pop>500 after got 10 digit in this range stop

[KSSV]

count = 0 ;
N = 10 ;
iwant = zeros(N,1) ;
for k1=1:100                      %set population generation limit her
    pop1h=randi([200 1150],1,1 );  %random genertor limit n*3 mean n-row and 3-three colum

      pop=pop1h*2 ;
      if pop > 500;
          count = count+1 ;
          iwant(count) = pop ;
          if count == N
              break
          end
      else
          continue
      end
  end

This can be achieved without loop also