How to build a growing square matrix with the following values?

1 view (last 30 days)
I am working on some code to find the condition of a spring matrix. I know the matrix in question, but I am not sure how to create a for-loop to make a bigger matrix after every iteration. In general, the matrix looks something this:
Considering the simple case where k1=k2=kn=1.
How would I go about constructing this matrix, computing a condition, then constructing a bigger matrix, computing the condition, and so on?

Accepted Answer

Akira Agata
Akira Agata on 17 Feb 2017
I think this code will generate the matrix.
n = 10;
k = ones(n+1,1);
for kk = 1:n
A = - diag(k(1:kk)) - diag(k(2:kk+1));
if kk>1
A = A + diag(k(2:kk),-1) + diag(k(2:kk),1);
end
% To display the matrix for each loop
A
end
The value k_1 ~ k_n in your picture corresponds to the array k in this script.

More Answers (0)

Categories

Find more on Programming in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!