How to define an array with multiple columns for each parameter in a for loop?
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I have a loop where each parameter should create an array with 20 columns so for n=1, there's 20 columns in the array, n=2, there's 20 columns in the array etc; so the final array should have 20*sz columns but am not sure how to code this (attempt below):
for n=1:sz
array(:,20]);
end
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Accepted Answer
James Tursa
on 9 Jan 2017
At each iteration, the array sub-section indexing would be:
array(:,n*20-19:n*20)
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