hello sir i want real values but when i write my function in matlab s(ii)==real (s(ii)); it give me complex value how to solve it

ii=1:2;
s(ii)=real(s(ii));   
s(ii)=round(log(z(ii))*N/j/2/pi)+1;

this is my short function please guide me where i am wrong

Answer 1

[Thorsten]

real is the real part of a complex number. Unless you do not have re-defined Matlab's real, this should work.

To check if you use the real "real", type

which real

Further, the lines

 s(ii)=real(s(ii)); 
 s(ii)=round(log(z(ii))*N/j/2/pi)+1;

don't make sense. The result would be the same without the first line, because s ist not used in the second line, so the s from the first line is simple replaced.

Do you want

   z(ii)=real(z(ii)); 
   s(ii)=round(log(z(ii))*N/j/2/pi)+1;

Also, if the argument of log is negative, the result will be complex. And round rounds, but does not discard the imaginary part. You can use abs or real, but of course I don't know if this is what you want to compute.

[Walter Roberson]

Perhaps you want to reverse the lines,

 s(ii)=round(log(z(ii))*N/j/2/pi)+1;
 s(ii)=real(s(ii));

[irfan]

sir thank you i understand your point