why type 2 FIR filter cannot be used to design high pass filter?

can anybody explain why type 2 FIR filter cannot be used to design high pass filter?

Answers (1)

This is because for Type II FIR, there is a zero corresponding to Nyqiust rate, i.e., half sampling frequency. However, a high pass filter needs to let that component pass, so it cannot be used for a high pass filter.

2 Comments

how does Z=-1 corresponds to nyqiust frequency?
You can think of the unit circle as the frequency axis. Starting from (1,0), which corresponds to the 0 frequency. If you travel along the circle and come back to the starting point, it corresponds to Fs. Therefore, half the circle is just Fs/2, which corresponds to z = -1. HTH

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on 14 Jan 2016

Commented:

on 14 Jan 2016

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