Substitute values in an array
3 views (last 30 days)
Show older comments
Hi guys,
I have a question.
I have an array like this:
d=[1 1 1 1 1 2 2 2 2 2 1 1 1 1 1 ]
How can i substitute the values of the array knowing that for the first 5 positions i want do to d=6 and for the last 4positions i want do do d=8? This means i can´t use d(d==1)= 6 because the values are different for each position...
Can anyone help?
Thanks in advance!
Inês
1 Comment
Stefan Raab
on 30 Nov 2015
Edited: Stefan Raab
on 30 Nov 2015
Hey, I am not sure if I get you right, but this might solve your problem:
d(1:5) = 6;
d((end-3):end) = 8;
Answers (1)
Stephen23
on 30 Nov 2015
Edited: Stephen23
on 30 Nov 2015
If you do not know the indices in advance then you can use diff and find:
>> d = [1,1,1,1,1,2,2,2,2,2,1,1,1,1,1];
>> f = find(diff(d));
>> d(1:f(1)) = 6;
>> d(1+f(end):end) = 8
d =
6 6 6 6 6 2 2 2 2 2 8 8 8 8 8
Or if the indices are known then they can be hardcoded:
>> d = [1,1,1,1,1,2,2,2,2,2,1,1,1,1,1];
>> d(1:5) = 6;
>> d(11:15) = 8
d =
6 6 6 6 6 2 2 2 2 2 8 8 8 8 8
0 Comments
See Also
Categories
Find more on Loops and Conditional Statements in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!