HELP to resolve this code
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m=original color image
en=enhanced color image
have written code for measure absolute mean brightness error(AMBE)
function E=eme(x,m)
em=mean2(x);
mm=mean2(m);
E=abs(em-mm);
end
Here E is absolute difference between mean brightness of two color images I think this code will take mean brightness of one channel of color image butcolor image has three channel so how will take the mean brightness value of all three channel
Answers (1)
Thorsten
on 29 Jun 2015
function d = brightnessdiff(I1, I2)
d = rgb2gray(I1) - rgb2gray(I2);
2 Comments
Image Analyst
on 29 Jun 2015
Brightness is not very precisely defined. Using rgb2gray() will give you the "brightness". You could also use rgb2lab() and use the L channel, or rgb2hsv() and use the V channel. It depends on what you want. Or perhaps you want to convert to LAB color space and look at the Delta E (color difference) which takes into account the total color difference, not just the brightness component. For example Delta E (like in my File Exchange) takes hue and chroma (saturation) into account, as well as brightness, in determining a total color difference.
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