How do I change all the elements in matrix with an index larger than a certain number to zero?

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I have trouble making a certain matrix even though it seems trivial. For my code I need to make a 4-D matrix A with dimensions 2x100xmax(K)xP where P=8 and K=round(linspace(1000,2000,P)) . The matrix needs to be all ones, except for K indexes larger than the K that corresponds with the P. For example, A(:,:,:,1) should be all ones except for K's larger than 1000 which should be zeros, and A(:,:,:,8) should be solely ones.
I tried code like
P = 8;
K = round(linspace(1000,2000,P));
A = zeros(2,100,max(K),P);
for i=1:P
A(:,:,:,i) = ones(2,N,K(i));
end
But as my command window showed that is clearly not the way to go.

Accepted Answer

Geoff Hayes
Geoff Hayes on 27 Jun 2015
Cyrustd - you almost have it, but I think that your code is just missing the range of the third dimension that you wish to be all ones. We know that
K =
1000 1143 1286 1429 1571 1714 1857 2000
so the third (K) indices that are one correspond to 1:1000, 1:1143, 1:1286, ... , and 1:2000. So we need to do something similar in for loop. Try the following
N = 100;
for u=1:P
A(:,:,1:K(u),u) = ones(2,N,K(u));
end
Note how we use 1:K(u) in the third indexing "dimension" of A which will correspond to the size of multidimensional array generated on the right-hand side of the equation.
  1 Comment
Cyrus Tirband
Cyrus Tirband on 28 Jun 2015
It works perfectly! It just made little sense too me earlier, but upon closer inspection it's pretty logical. I got my own code in the question working a little earlier by adding these in my loop
for i=1:P
B = ones(2,N,K(i));
B(:,:,max(K)) = 0;
A(:,:,:,i) = B;
end
But yours is faster (which was important for my assignment!) and offers more insight. Thanks!

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