HI, i want to plot x=sin(t*pi) fuction like this picture for t[0:1:24] and x will be 0 when t=17
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![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/150847/image.png)
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Accepted Answer
Joseph Cheng
on 4 Jun 2015
Edited: Joseph Cheng
on 4 Jun 2015
figure out what azzi was doing in the math which would lead you to figure out what to change.
t=0:0.01:24
y=sin(t*pi).*(t<15) + 3*sin(t*pi).*(t>=15)
plot(t,y)
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More Answers (1)
Azzi Abdelmalek
on 4 Jun 2015
t=0:0.01:24
y=sin(t*pi).*(t<17)
plot(t,y)
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Image Analyst
on 5 Jun 2015
david's two "Answers" moved here: because they are comments (replies) to Azzi and not "Answers" to his original question at the top of the page.
thank you Mr.AZZI i'm really satisfied with your answer so if I want to change the amplitude at t = 15 like this picture
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/183857/image.png)
y=sin(t*pi) for 0<t<15
y=3*sin(t*pi) for t>15
thank you very much . my last question is if i want to change the amplitude of sinus 7 times 0<t<38
first for 0<t<10 y= sin(t*pi)
and for 10<t<15 y=2*sin(t*pi)
and for 15<t<19 y=5*sin(t*pi)
and for 19<t<24 y=sin(t*pi)
and for 24<t<27 y=0
and for 27<t<35 y=4*sin(t*pi)
and for 35<t<38 y=0
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