Character string to numeric vector

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Roderick
Roderick on 20 Sep 2024
Edited: Stephen23 on 20 Sep 2024
Dear all
I am extracting from a file in a for loop information in the following form: ' ( 0.0357 -0.0001 0.0051) ', which is a 1x27 char. I would like to store the three displayed numbers in a the three components of an array so I can use these figures to do mathematical operations. How could I transform them to do so in this case, keeping the minus signs that can appear for different steps of the for loop too?
  1 Comment
Stephen23
Stephen23 on 20 Sep 2024
@Richard Wood: please upload an unaltered sample data file by clicking the paperclip button.

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Answers (2)

Stephen23
Stephen23 on 20 Sep 2024
Edited: Stephen23 on 20 Sep 2024
txt = ' ( 0.0357 -0.0001 0.0051) '
txt = ' ( 0.0357 -0.0001 0.0051) '
vec = sscanf(txt(3:end),'%f',[1,3])
vec = 1×3
0.0357 -0.0001 0.0051
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or
vec = sscanf(strtrim(txt),'(%f%f%f',[1,3])
vec = 1×3
0.0357 -0.0001 0.0051
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Sameer
Sameer on 20 Sep 2024
Hi Richard,
To extract the numbers from the string and store them in an array, you can use the "sscanf" function
Here's how you can do it:
% Example string
str = ' ( 0.0357 -0.0001 0.0051) ';
% Use sscanf to extract the numbers
numbers = sscanf(str, ' ( %f %f %f) ');
disp(numbers);
Please refer to the below MathWorks documentation link:
Hope this helps!

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