Extract Numbers from Mixed string
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Hello, I have this string
'single snap detector: 1 S2L:232867 S2R:3151621 S3L:0 S3R:0'
Whats the best way to get the 4 numbers and then the S2R - S2L value?
I have tried this:
B='single snap detector: 1 S2L:232867 S2R:3151621 S3L:0 S3R:0'
pat=regexpPattern("S2L:[/d]")
extract(B,pat)
But Im getting an empty array
Accepted Answer
Hassaan
on 9 Feb 2024
% Your input string
B = 'single snap detector: 1 S2L:232867 S2R:3151621 S3L:0 S3R:0';
% Regular expression pattern to match the labels and their corresponding values
pattern = 'S2L:(\d+) S2R:(\d+) S3L:(\d+) S3R:(\d+)';
% Using regexp to find the matches and extract the numbers
tokens = regexp(B, pattern, 'tokens');
% tokens{1} will contain a cell array of the matched groups if a match is found
if ~isempty(tokens)
% Converting the extracted strings to numbers
numbers = str2double(tokens{1});
S2L = numbers(1);
S2R = numbers(2);
S3L = numbers(3);
S3R = numbers(4);
% Calculate S2R - S2L
difference = S2R - S2L;
else
S2L = NaN;
S2R = NaN;
S3L = NaN;
S3R = NaN;
difference = NaN;
end
% Displaying the results
S2L, S2R, S3L, S3R, difference
-----------------------------------------------------------------------------------------------------------------------------------------------------
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More Answers (3)
Stephen23
on 9 Feb 2024
Edited: Stephen23
on 9 Feb 2024
B = 'single snap detector: 1 S2L:232867 S2R:3151621 S3L:0 S3R:0';
Method one: SSCANF:
V = sscanf(B,'%*[^:]:%d') % very efficient
Method two: REGEXP (could also be EXTRACT):
T = regexp(B,'(S\w+):(\d+)','tokens');
T = vertcat(T{:}) % all relevant parts
V = str2double(T(:,2))
3 Comments
Mathieu NOE
on 9 Feb 2024
hello
i supposed you wanted to do this :
B='single snap detector: 1 S2L:232867 S2R:3151621 S3L:0 S3R:0'
% pat=regexpPattern("S2L:[/d]")
pat=regexpPattern("S2L:[\d]")
extract(B,pat)
my2 cents suggestion to extract all numbers present in this char array (up to you to pick the ones you are intersted in);
B='single snap detector: 1 S2L:232867 S2R:3151621 S3L:0 S3R:0'
C = regexp(B,'\d+(\.)?(\d+)?','match');
% convert string to num array
for ci = 1:numel(C)
out(ci,:) = str2double(C{ci});
end
out
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