Accessing all fields within a struct level at once

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If I have a struct A which looks like:
A.('one').('include') ; A.('two').('include'); A.('three').('dont include');
and so on, how can I directly check if 'dont include' is present in the third level of the structure without having to use a loop. Is this possible to achieve without implementing a loop?
  2 Comments
Voss
Voss on 19 Dec 2023
'dont include' is not a valid field name, so what does the struct really look like?
Rather than describing the struct, maybe it's better to save it in a .mat-file and upload it here (using the paperclip button).

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Accepted Answer

Stephen23
Stephen23 on 19 Dec 2023
Edited: Stephen23 on 19 Dec 2023
"Is this possible to achieve without implementing a loop?"
Not really, but you can hide the loop using STRUCTFUN:
A.one.include = 1;
A.two.include = 2;
A.three.dontinclude = 3;
F = @(s)isfield(s,'dontinclude');
structfun(F,A)
ans = 3×1 logical array
0 0 1
  2 Comments
Vaishnavi
Vaishnavi on 19 Dec 2023
Hi, this is how my mat file looks like in reality
Stephen23
Stephen23 on 19 Dec 2023
"Hi, this is how my mat file looks like in reality"
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More Answers (1)

Nipun
Nipun on 21 Dec 2023
Edited: Nipun on 21 Dec 2023
Hi Vaishnavi,
I understand that you are trying to find if "dontinclude" is a structure property without using for loops.
One possible solution is to create a function which evaluates every level of structure to check if the property is present.
Here is an example code with the listed recommendation
funcCheck = @(struct)isfield(struct,'dontinclude');
structfun(funcCheck,A)
Returns a "n x 1" logical array, where "n" is the number of levels in the structure.
Link to documentation:
  1. STRUCTFUN : Apply function to each field of scalar structure - MATLAB structfun - MathWorks India
Hope this helps.
Regards,
Nipun

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