Hi. How do I maintain the square wave output of the 1-D?

the blue triangular waveform is the waveform of 1-D, and the red square wave is the D

2 Comments

it's already right that the D and 1-D waveforms are out of phase but the 1-D waveform is not in square wave

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 Accepted Answer

Not sure which block you are using beefore to Goto "[delay]" block but removing data conversion and this phase shift block. The Delay signal would be out of phase with the D signal. Treating the signals as boolean signals with 0s and 1s.

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