Why I'm getting a complex degree value while using "acos"?
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% To reproduce the snippet, you can use below code
XYZc = [2489011.31135707, 7440368.1011554, 17.6551714555564];
X0 = 2489018.662
Y0 = 7440333.989
Z0= 10.091
dir_vec1 = XYZc-[X0, Y0, Z0];
dir_mag1= norm(dir_vec1);
dir_vec2 = [0,XYZc(2),0]-[X0, Y0, Z0];
dir_mag2= norm(dir_vec2);
alpha = acosd(dir_mag2/dir_mag1)
1 Comment
Matt J
on 10 Jun 2023
I have edited your post for you to make your code output visible. It is always advisable to do this so we can see what output you are talking about.
Accepted Answer
Matt J
on 10 Jun 2023
Edited: Matt J
on 10 Jun 2023
Because abs(dir_mag2/dir_mag1) is greater than 1.
abs(dir_mag2/dir_mag1)
13 Comments
Image Analyst
on 11 Jun 2023
It's not in the comments, neither his nor yours. It should be above, at the very first answer post of @Matt J
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