Clear Filters
Clear Filters

Differential equation of second order with two variables

9 views (last 30 days)
to be solved is the equation ๐ธ๐ผ๐‘ค4(๐‘ฅ,๐‘ก)+๐‘š ๐‘คฬˆ(๐‘ฅ,๐‘ก)=0 and this can be solved by expressing ๐‘ค(๐‘ฅ,๐‘ก)= ๐œ™(๐‘ฅ)โ‹…๐‘Œ(๐‘ก)
for ๐œ™(๐‘ฅ) we do have this expression ๐œ™๐‘–(๐‘ฅ)=๐ดโ‹…[sin(๐œ†๐‘– ๐‘ฅ๐ฟ)โˆ’sinh(๐œ†๐‘– ๐‘ฅ๐ฟ)+sin(๐œ†๐‘–)+sinh(๐œ†๐‘–)cos(๐œ†๐‘–)+cosh(๐œ†๐‘–)โ‹…(cosh(๐œ†๐‘– ๐‘ฅ๐ฟ)โˆ’cos(๐œ†๐‘–๐‘ฅ๐ฟ)) ]
and for ๐‘Œ๐‘–(๐‘ก)=๐‘Œ(0)cos(๐œ”๐‘– ๐‘ก)+๐‘Œฬ‡(0)๐œ”sin(๐œ”๐‘–(๐‘ก))=๐ถ(0)โ‹…๐‘๐‘œ๐‘ (๐œ”๐‘– ๐‘ก+๐œƒ(0)). Whereas ๐œ†๐‘– is solved through this equation 1+cos(๐œ†๐‘–)โ‹…cosh(๐œ†๐‘–)=0
I am guessing that to solve the first differential equation as conditions we can use the three other equations given.
Does anyone has some tipps how this differential equation can be solved?

Answers (1)

Pranjal Saxena
Pranjal Saxena on 28 Jul 2023
Hi Florian,
I understand that you want to solve this second order differential equation.
You can use the โ€œSymbolic Math Toolboxโ€ in MATLAB to do so.
A typical approach to solving higher-order ordinary differential equations is to convert them to systems of first-order differential equations, and then solve those systems.
First you need to convert the second-order differential equation into a system of differential equations that can be solved using the numerical solver โ€œode45โ€ of MATLAB.
You can refer to the following MATLAB documentations for more information:
I hope this helps.
Warm Regards,
Pranjal.

Categories

Find more on Symbolic Math Toolbox in Help Center and File Exchange

Products


Release

R2022b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!