How can I write y0 code in one line and still I can get this output.

y0= [ (1e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(1e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(1e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1)); ]
================================================
output
y0 = 0.0016
0.0079
0.6824
0.0017
0.0060
1.2281
0.0069
0.0075
-1.1515

Answers (1)

y0= [ (1e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(1e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(1e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1)); ]
y0 = 9×1
0.0082 0.0023 -0.4870 0.0071 0.0082 1.1632 0.0008 0.0039 1.7553
y0 = [1e-2*rand(6,1);repmat((-3.14)*rand(1)+(3.14)*rand(1),3,1)]
y0 = 9×1
0.0018 0.0012 0.0068 0.0078 0.0044 0.0079 -1.7388 -1.7388 -1.7388

3 Comments

y0= [ (1e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(1e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(1e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1)); ]
y0 = 9×1
0.0031 0.0010 0.8000 0.0083 0.0089 1.8618 0.0020 0.0010 1.6583
%
y0 = [1e-2*rand(6,1);[(-3.14)*rand(1)+(3.14)*rand(1)].*rand(3,1)]
y0 = 9×1
0.0096 0.0081 0.0060 0.0044 0.0098 0.0030 -0.3596 -0.0365 -0.3486
Here I'm having same problem that you have, the first two no.
0.0031
0.0010
0.8000
0.0083
0.0089
1.8618
0.0020
0.0010
1.6583
are less than 0.0031 but the 3rd no. is between -3.14 to 3.14,
therefore I want to modify my code in such manner that I can satisfy my given condition.
how is it less than 0.0031 ? take a look at the values, they are just randome values multiplied by 1e-2. if you want the first two values to higher than 0.0031, then you can use randi instead of rand
y0 = [ 0.0096
0.0081
0.0060
0.0044
0.0098
0.0030
-0.3596
-0.0365
-0.3486]
y0 = 9×1
0.0096 0.0081 0.0060 0.0044 0.0098 0.0030 -0.3596 -0.0365 -0.3486
y0 = [1e-2*randi([0 10],6,1);[(-3.14)*rand(1)+(3.14)*rand(1)].*rand(3,1)]
y0 = 9×1
0.0700 0.1000 0.0500 0.0600 0.0600 0.0700 -0.2265 -0.4150 -0.3119

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