What's wrong with this expression?
1 view (last 30 days)
Show older comments
Hello,
I have a vector x=[0:1:1000] and I would like to write the general expression of Gaussian(a,b,c,x) vector where a,b,c are its parameters that I can define time by time. Then I should plot it. The main problem is to write the expression
y=a*'exp(-(x-b)*'(x-b)/'(c*c))
that is in this way, not correct.. Thanks Bye Marco
0 Comments
Answers (2)
Roger Stafford
on 1 Apr 2015
Edited: Roger Stafford
on 1 Apr 2015
y=a*exp(-(x-b).^2/c^2);
0 Comments
Adam Wyatt
on 1 Apr 2015
Are a, b, & c scalars. If so: y = a*exp(-((x-b)/c).^2);
However, a more general version makes use of bsxfun ( see this post ) so that it can accept variable inputs:
% Search documentation for anonymous functions
Gaussian = @(A, x0, dx, x) bsxfun(@times, A, exp(-bsxfun(@rdivide, bsxfun(@minus, x, x0), dx).^2));
Lets say you wanted to generate a Gaussian at different central positions:
x = (0:1000).'; % x is a column vector - good practise to use column vectors
x0 = [300; 500; 600]; % x0 is a column vector
y = Gaussian(1, x0.', 100, x); % y is a 2D matrix with x (the domain) down the columns, x0 along the rows
plot(x, y); % Plot three shifted Gaussians
0 Comments
See Also
Categories
Find more on Data Preprocessing in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!