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loop to calculate time using previous values

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Hello everyone!
Could you please help me with a code.
I have a loop and calculated time, so the values of time are the increments between the current and previous values. So how to generate the loop for the time where the previous ones can be added. For example, my first t values are 60.6664, 60.9712, 61.2792, 61.5902, 61.9045........ In the result of new time will be 60.9712, (60.9712+61.2792), (60.9712+61.2792+61.5902)......
W_takeoff = 10000;
W_landing=6000;
S = 20;
AR = 5;
cd0 = 0.02;
k = 1/pi/AR;
RC=0.51;
clalpha = 2*pi;
amin=2;
astall=12;
rho=1;
ct=0.001;
alpha_max=2.95;
cl_max=clalpha*alpha_max*pi/180;
cd_max = cd0 + k * cl_max * cl_max;
delta_w=50;
j=0;
for w=W_takeoff:-delta_w:W_landing
j=j+1;
V(j) = sqrt(2*w/rho/S/cl_max);
D(j) = 0.5 * rho * V(j) * V(j) * S * cd_max;
Thrust(j)=D(j); %for steady level flight condition
F(j)=ct*Thrust(j); %fuel consumption
Weight(j)=w;
t(j)=delta_w/F(j);
R(j)=V(j)*t(j);
end

Answers (1)

Dyuman Joshi
Dyuman Joshi on 31 Mar 2023
Edited: Dyuman Joshi on 31 Mar 2023
You can vectorize the loop -
W_takeoff = 10000;
W_landing = 6000;
S = 20;
AR = 5;
cd0 = 0.02;
k = 1/pi/AR;
RC=0.51;
clalpha = 2*pi;
amin=2;
astall=12;
rho=1;
ct=0.001;
alpha_max=2.95;
cl_max=clalpha*alpha_max*pi/180;
cd_max = cd0 + k * cl_max * cl_max;
delta_w=50;
j=0;
w=W_takeoff:-delta_w:W_landing;
V = (2*w/rho/S/cl_max).^(1/2);
D = 0.5*rho*V.^2*S*cd_max;
Thrust = D;
F = ct*Thrust;
Weight = w;
t = delta_w./F
t = 1×81
60.6664 60.9712 61.2792 61.5902 61.9045 62.2219 62.5427 62.8667 63.1941 63.5250 63.8593 64.1972 64.5387 64.8838 65.2327 65.5853 65.9417 66.3020 66.6663 67.0347 67.4071 67.7837 68.1645 68.5496 68.9391 69.3330 69.7315 70.1345 70.5423 70.9548
R = V.*t;
%new time
T = cumsum(t)
T = 1×81
1.0e+03 * 0.0607 0.1216 0.1829 0.2445 0.3064 0.3686 0.4312 0.4940 0.5572 0.6208 0.6846 0.7488 0.8134 0.8782 0.9435 1.0091 1.0750 1.1413 1.2080 1.2750 1.3424 1.4102 1.4784 1.5469 1.6158 1.6852 1.7549 1.8250 1.8956 1.9665
  2 Comments
Alina Abdikadyr
Alina Abdikadyr on 31 Mar 2023
Thank you! but the results from loop and your method are different
Dyuman Joshi
Dyuman Joshi on 31 Mar 2023
Edited: Dyuman Joshi on 4 Apr 2023
Apologies, @Alina Abdikadyr, there was a mistake in the formula of V which has been rectified. Please check my answer again.

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