# How to do the following two for loop?

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M on 9 Feb 2023
Commented: M on 10 Feb 2023
How to do the following two for loop?
i=0.1:0.1:0.9 ;
M=[1 1 1 1 1 1];
first outer loop :
In the 1st inner loop Assign i=0.9 on the first element, then in the 2nd inner loop Assign 0.8 on the first element till 0.1
then 2nd outer loop
In the 1st inner loop Assign i=0.9 on the 2nd element, in the 2nd inner loop Assign 0.8 on the 2nd element till 0.1
.
.
and so on .. till the 6th outer loop

Torsten on 9 Feb 2023
You mean
i=0.1:0.1:0.9 ;
M = [i.',ones(numel(i),5)]
M = 9×6
0.1000 1.0000 1.0000 1.0000 1.0000 1.0000 0.2000 1.0000 1.0000 1.0000 1.0000 1.0000 0.3000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 0.5000 1.0000 1.0000 1.0000 1.0000 1.0000 0.6000 1.0000 1.0000 1.0000 1.0000 1.0000 0.7000 1.0000 1.0000 1.0000 1.0000 1.0000 0.8000 1.0000 1.0000 1.0000 1.0000 1.0000 0.9000 1.0000 1.0000 1.0000 1.0000 1.0000
?
Torsten on 10 Feb 2023
Edited: Torsten on 10 Feb 2023
That's exactly what the code does (see above).
Or do you want the element of the outer loop remain at 0.1 instead of resetting it to 1 ?
Then delete the line
M(i) = 1.0;
M on 10 Feb 2023
@Torsten yes i deleted that line and now its working good. Thanks

Image Analyst on 9 Feb 2023
Don't call variables "i" -- it's the imaginary constant.
Try this, for example to multiply M by 2
vec = 0.1:0.1:0.9
vec = 1×9
0.1000 0.2000 0.3000 0.4000 0.5000 0.6000 0.7000 0.8000 0.9000
M = [vec 1 1 1 1 1]
M = 1×14
0.1000 0.2000 0.3000 0.4000 0.5000 0.6000 0.7000 0.8000 0.9000 1.0000 1.0000 1.0000 1.0000 1.0000
result = M * 2
result = 1×14
0.2000 0.4000 0.6000 0.8000 1.0000 1.2000 1.4000 1.6000 1.8000 2.0000 2.0000 2.0000 2.0000 2.0000
% Or via a for loop
for k = 1 : numel(vec)
result(k) = 2 * M(k);
end
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Image Analyst on 10 Feb 2023
"assign i=0.9 on the first element, then assign 0.8 on the first element till 0.1"
Try this
for k = 1 : 9
result(k) = (10 - k) * 0.1;
end
result
result = 1×9
0.9000 0.8000 0.7000 0.6000 0.5000 0.4000 0.3000 0.2000 0.1000
M on 10 Feb 2023
I want to move into M=[i 1 1 1 1 1], it is an input for another function
Image Analyst on 10 Feb 2023
OK, so did you do it? Again, don't use "i" as the name of your variable. That is something everyone here advises against.
for k = 1 : 9
result(k) = (10 - k) * 0.1;
end
M = [result, 1 1 1 1 1]