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I am having an array with positive integers, and i want to know all the possibility that the sum of elements of the array is close to or equal to a number say (N))

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I am having an array with positive integers, and i want to know all the possibility that the sum of elements of the array is close to or equal to a number say (N)) and no index (element in the array) will be repeated
A = [ 0 7 30 16 23 11 19 15 28 8 8 7 14 6 19 11 12 26 17 6 15 5 10 ]
N = 40 (or close to 40 like 36,37,38,39)
the possible sum of the numbers are like
8+6+26 = 40
23+15 = 38
16+17+6=39
15+5+19=39
and so on
  4 Comments
Matt J
Matt J on 5 Jan 2023
Edited: Matt J on 5 Jan 2023
Why is 23+15 = 38 an acceptable selection when it is still possible to add further A(i) to the sequence without exceeding N=40? In particular: 23+15+0 = 38

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Accepted Answer

Matt J
Matt J on 5 Jan 2023
Edited: Matt J on 6 Jan 2023
N=40;
A = [1 7 13 20 38 39 40];
A=unique(A);
n=find(cumsum(A)<=N,1,'last');
result=cell(n,1);
for i=1:n
tmp=subCollection(N,A,i);
tmp(:,end+1:n)=nan;
result{i}=tmp;
end
result=cell2mat(result) %final result
result = 7×3
40 NaN NaN 1 38 NaN 1 39 NaN 1 7 13 1 7 20 1 13 20 7 13 20
function T=subCollection(N,A,m)
J=nchoosek(1:numel(A),m);
I=repmat( (1:height(J))' ,1,m);
%S=sparse(I,J,1);
S=accumarray([I(:),J(:)],1);
delta=N-S*A(:);
C=(1./(1-S));
mincomp=min( C.*A(:).' ,[],2);
idx=delta<mincomp & delta>=0;
T=(1./S).*A(:).';
T=sort(T(idx,:),2);
T(isinf(T))=nan;
T=T(:,1:m);
end
  2 Comments
Ashish Verma
Ashish Verma on 7 Jan 2023
According to me results will be some matrices, where the sum will be close to 40 and the matrix contains distinct elements or no index of array will be repeated (because of duplicacy). For eg, possibility of 3 elements sum will be
[8+6+26 = 40
23+15 = 38
16+17+6=39
15+5+19=39
...]

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