I wrote a code to get the value of M less than 0.6, but How can I modify the code so that I can get the value of M which lie between 0.5 to 0.6 ?,

ti = 0;
tf = 70E-8;
tspan=[ti tf];
KC = 1E-3;
for j = 1:100
y0= [(10e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
      (10e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
      (10e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
      (10e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
      (10e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
      (10e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
      (10e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
      (10e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
      (10e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
      (10e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
      (10e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
      (10e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
      (10e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
      (10e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
      (10e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
      (10e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
      (10e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
      (10e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
      (10e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
      (10e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
      ((-3.14).*rand(20,1) + (3.14).*rand(20,1))];
yita_mn = [
    0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1;
    1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0;
    0 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0;
    0 0 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0;
    0 0 0 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0;
    0 0 0 0 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0;
    0 0 0 0 0 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0;
    0 0 0 0 0 0 1 0 1 0 0 0 0 0 0 0 0 0 0 0;
    0 0 0 0 0 0 0 1 0 1 0 0 0 0 0 0 0 0 0 0;
    0 0 0 0 0 0 0 0 1 0 1 0 0 0 0 0 0 0 0 0;
    0 0 0 0 0 0 0 0 0 1 0 1 0 0 0 0 0 0 0 0;
    0 0 0 0 0 0 0 0 0 0 1 0 1 0 0 0 0 0 0 0;
    0 0 0 0 0 0 0 0 0 0 0 1 0 1 0 0 0 0 0 0;
    0 0 0 0 0 0 0 0 0 0 0 0 1 0 1 0 0 0 0 0;
    0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 1 0 0 0 0;
    0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 1 0 0 0;
    0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 1 0 0;
    0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 1 0;
    0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 1;
    1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0
    ]*(KC);
N = 20;
tp = 1E-12;
o = sort(10e2*rand(1,20),'ascend');
[T,Y]= ode45(@(t,y) rate_eq(t,y,yita_mn,N,o),tspan./tp,y0);

r = ((1/20).*( exp(i.*Y(:,3)) + exp(i.*Y(:,6)) + exp(i.*Y(:,9)) + exp(i.*Y(:,12)) + exp(i.*Y(:,15)) ...
    +exp(i.*Y(:,18)) +exp(i.*Y(:,21)) +exp(i.*Y(:,24)) + exp(i.*Y(:,27)) + exp(i.*Y(:,30)) + exp(i.*Y(:,33)) ...
    + exp(i.*Y(:,36)) + exp(i.*Y(:,39)) +exp(i.*Y(:,42)) + exp(i.*Y(:,45)) + exp(i.*Y(:,48)) + exp(i.*Y(:,51)) + exp(i.*Y(:,54))+ exp(i.*Y(:,57)) + exp(i.*Y(:,60))));



M(j) = max(abs(r));
end

% I want those value between 0.5 to 0.6, how can I do that?
n = M(M<0.6)


function dy = rate_eq(t,y,yita_mn,N,o)

dy = zeros(4*N,1);
dGdt = zeros(N,1);
dAdt = zeros(N,1);
dOdt = zeros(N,1);
P = 1;
a = 1;
T = 2000;
tp = 1E-12;
Gt = y(1:3:3*N-2);
At = y(2:3:3*N-1);
Ot = y(3:3:3*N-0);
k = 1E-3;
for i = 1:N
    dGdt(i) = (P - Gt(i) - (1 + 2.*Gt(i)).*((At(i)))^2)./T ;
    dAdt(i) = Gt(i)*(At(i));
    dOdt(i) = -a.*Gt(i) + o(1,i).*tp;  
    for j = 1:N
        dAdt(i) = dAdt(i) + yita_mn(i,j)*(At(j))*cos(Ot(j)-Ot(i));
        dOdt(i) = dOdt(i) + yita_mn(i,j)*((At(j)/At(i)))*sin(Ot(j)-Ot(i));
    end
end
dy(1:3:3*N-2) = dGdt;
dy(2:3:3*N-1) = dAdt;
dy(3:3:3*N-0) = dOdt;

n1 = (1:20)';
n2 = circshift(n1,-1);
n61 = n1 +60;
n62 = circshift(n61,-1);
n80 = circshift(n61,1);

j2 =  3*(1:20)-1;
j5 = circshift(j2,-1);
j8 = circshift(j2,-2);
j59 = circshift(j2,1);

dy(n61) = (o(1,n2).' - o(1,n1).').*tp - a.*(Gt(n2) - Gt(n1)) - (k).*(y(j2)./y(j5)).*sin(y(n61)) - (k).*(y( j5)./y(j2)).*sin(y(n61)) + (k).*(y(j8)./y(j5)).*sin(y(n62)) - (k).*(y(j59)./y(j2)).*sin(y(n80));  
end

Answer 1

[Image Analyst]

Try this

M = rand(6)

M = 6×6

0.4981 0.1748 0.5274 0.2588 0.0256 0.8047 0.5549 0.2718 0.5634 0.3848 0.9192 0.5669 0.3199 0.4258 0.0928 0.0369 0.5816 0.0009 0.9879 0.5313 0.3875 0.9770 0.6493 0.4357 0.2661 0.8631 0.5638 0.0952 0.7421 0.7805 0.3278 0.7367 0.3974 0.5681 0.0897 0.6884

mask = M > 0.5 & M < 0.6

mask = 6×6 logical array
   0   0   1   0   0   0
   1   0   1   0   0   1
   0   0   0   0   1   0
   0   1   0   0   0   0
   0   0   1   0   0   0
   0   0   0   1   0   0

valuesInRange = M(mask)

valuesInRange = 8×1

0.5549 0.5313 0.5274 0.5634 0.5638 0.5681 0.5816 0.5669