How does the cycle for , if work?
14 views (last 30 days)
Show older comments
Dear All, I have n=[0:1:10] and the column K=[-2,5,-5]. I would like to generate a cycle in which each time It takes an item of n and adds it to K, every time It checks if the sum(K) is zero: if it is zero it must write the value of "n".
I wrote this but it doesn't work:
for n=0:1:10
K=[-2,5,-5];
Z=K+n;
S=sum(Z);
if S==0
n
end
end
Could you help me, please.
Thanks in advance
Best regards
Massimo
0 Comments
Answers (2)
Adam
on 13 Mar 2015
K=[-2,5,-5];
n = 0:10'
res = bsxfun( @plus, K, n' );
resSum = sum( res, 2 );
zeroSums = resSum == 0;
n( zeroSums )
should give you the result you want without needing a loop, if I understand your requirements correctly.
James Tursa
on 13 Mar 2015
The reason it doesn't produce any output is because the sum is never 0. E.g., print out S each iteration to see what is going on:
for n=0:1:10
K=[-2,5,-5];
Z=K+n;
S=sum(Z);
disp(S);
if S==0
n
end
end
If you think the sum should have been 0 at some point, then you need to re-examine your algorithm and the problem you are solving.
See Also
Categories
Find more on Matrices and Arrays in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!