Using load for different files with varying names

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I have 25 files with .mat files, naming from data1 to data25
how to load them properly without manualy typing from 1 to 25
Here is my idea and the error
```
for i = 1:1:25
load('data%d.mat',i)
end
```
Error using load
Must be a text scalar.

Accepted Answer

Akira Agata
Akira Agata on 13 Sep 2022
How about the following?
for kk = 1:25
fileName = sprintf('data%d.mat', kk);
load(fileName)
%
% Some process for each file
%
end
  2 Comments
Stephen23
Stephen23 on 14 Sep 2022
Edited: Stephen23 on 14 Sep 2022
@Miraboreasu: Note that LOADing directly into the workspace often leads to problems processing the loaded data, exactly as your follow-up question indicates:
It is strongly recommended to LOAD into an output variable:
S = load(..)
and then access the fields of S.
Akira Agata
Akira Agata on 14 Sep 2022
Yes, of course it is recommended to load into an output variable, as you mentioned.
Thank you for your additional comment !

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