How to convert irregular daily data to annual data?

Hi All!
I have a dataset (excel file attached - pcr.xlsx) of daily data values. The values are expressed as "Tonnes". I wanted to convert these to annual data from 1959 till date. My issue is that the daily data are irregular i.e. each year does not contain 365/366 values, so I am confused on how to directly get the answer (if each year had constant number of data points - 365, I think it would be easier).
I did try the "convert2annual" function but had no luck with it. I would appreciate some help in this regard. Thank you!

 Accepted Answer

T = readtable("https://www.mathworks.com/matlabcentral/answers/uploaded_files/1101770/pcr.xlsx");
T(T.Tonnes == 0, :) =[]; % remove rows where Tonnes == 0
head(T)
ans = 8×2 table
Dates Tonnes ______________ ______ {'25-07-1959'} 319.76 {'25-07-1959'} 319.76 {'25-07-1959'} 4268.3 {'25-07-1959'} 2926.8 {'25-07-1959'} 3963.4 {'25-07-1959'} 1585.4 {'25-07-1959'} 975.7 {'25-07-1959'} 1524.4
T1 = timetable(datetime(T.Dates, "InputFormat", 'dd-MM-yyyy'), T.Tonnes);
T1.Properties.VariableNames = "Tonnes";
T2 = retime(T1, 'yearly', 'mean')
T2 = 61×1 timetable
Time Tonnes ___________ ______ 01-Jan-1959 1425.8 01-Jan-1960 2580.8 01-Jan-1961 1813.5 01-Jan-1962 2659.8 01-Jan-1963 1656.8 01-Jan-1964 1409.7 01-Jan-1965 1727.9 01-Jan-1966 1271.6 01-Jan-1967 1430.1 01-Jan-1968 1102.1 01-Jan-1969 1678.4 01-Jan-1970 1316.5 01-Jan-1971 1369.1 01-Jan-1972 1329.6 01-Jan-1973 1031.2 01-Jan-1974 1420.3

3 Comments

Thanks @Chunru for your answer. However, there's a slight issue. I have re-attached the file here.
In the "Tonnes" column, there are zeros, so I wanted to take the annual mean by ignoring the zeros. I tried splitting the columns and used:
tonnes(tonnes==0) = []
But this eliminated the rows in the process. Could you please help me in calculating the annual means by ignoring the zeros in the "Tonnes" column?
You can remove those rows in table before retime as updated above.
Thanks you @Chunru I understood where I went wrong.

Sign in to comment.

More Answers (0)

Categories

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!