A compact way to extract a date from a filename and transform it into a datetime

A compact way to extract a date from a filename and transform it into a datetime ?

E.g. from

'20210317.csv'

to

ans = 
datetime
17-Mar-2021

Answer 1

[Sim]

found it:

s = '20210317';
datetime(s, 'InputFormat', 'yyyyMMdd')

which gives this:

ans = 
   datetime
   17-Mar-2021

[Stephen23]

s = '20210317.csv';
d = datetime(s, 'InputFormat', 'yyyyMMdd''.csv''')

d = datetime
   17-Mar-2021

[Sim]

oh, even better by including the

''.csv''

I would accept your version...!