how can I choose values from a vector ascendingly and concequently ?

        X = [-28.6479 -27.5 -18.33 -13.75 -11 -9.16 -7.85 -6.87 -6.11 -5.5 5.5 6.11 6.87 7.85 9.16 11 13.75 18.33 27.5 28.6479]

Answer 1

[Voss]

X = [-28.6479 -27.5 -18.33 -13.75 -11 -9.16 -7.85 -6.87 -6.11 -5.5 5.5 6.11 6.87 7.85 9.16 11 13.75 18.33 27.5 28.6479]

X = 1×20

-28.6479 -27.5000 -18.3300 -13.7500 -11.0000 -9.1600 -7.8500 -6.8700 -6.1100 -5.5000 5.5000 6.1100 6.8700 7.8500 9.1600 11.0000 13.7500 18.3300 27.5000 28.6479

% choose three consecutive elements from X, starting with element 5:
choice = X(5:7)

choice = 1×3

-11.0000 -9.1600 -7.8500

[omar th]

first thank you for your fast response, but I want to choose only one value each iteration because this vector inside while loop. for example, in the first step I want choose -28.6479 in the second step I want to choose -27.5 and so forth up to choosing the final value in the vector which is -28.6479

[Voss]

X = [-28.6479 -27.5 -18.33 -13.75 -11 -9.16 -7.85 -6.87 -6.11 -5.5 5.5 6.11 6.87 7.85 9.16 11 13.75 18.33 27.5 28.6479]

X = 1×20

-28.6479 -27.5000 -18.3300 -13.7500 -11.0000 -9.1600 -7.8500 -6.8700 -6.1100 -5.5000 5.5000 6.1100 6.8700 7.8500 9.1600 11.0000 13.7500 18.3300 27.5000 28.6479

for current_index = 1:numel(X)
    choice = X(current_index)
end

choice = -28.6479

choice = -27.5000

choice = -18.3300

choice = -13.7500

choice = -11

choice = -9.1600

choice = -7.8500

choice = -6.8700

choice = -6.1100

choice = -5.5000

choice = 5.5000

choice = 6.1100

choice = 6.8700

choice = 7.8500

choice = 9.1600

choice = 11

choice = 13.7500

choice = 18.3300

choice = 27.5000

choice = 28.6479