# How to apply moving harmonic average on an array?

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Nisar Ahmed on 3 Jul 2022
Edited: dpb on 4 Jul 2022
Hi,
I have attached the data Kd_i = (115*1), I want to keep first and last values as it is in the data (or also shown in the figure below) and in the row want compute the harmonic average of first and second values (red square), in the 3rd row I want to compute the harmonic average of second and thrid values (green square) asn so on...
I mean first and last values remain same (just to have final array/vector of equal length), and then from second row it moves the by computing the harmonic mean of first and second row, until second last row. Can someone help me to write it code?
Thanks Abhishek Tiwari on 3 Jul 2022
Hi,
A 'For' loop and harmmean() may do the same thing, as shown.
n = numel(Kd_i);
harmonicMean = Kd_i;
for idx = 2:n-1
harmonicMean(idx) = harmmean(Kd_i(idx-1 : idx, 1));
end
Nisar Ahmed on 4 Jul 2022
thanks

### More Answers (2)

Star Strider on 3 Jul 2022
If you want to calculate it as described in the harmmean More About section, perhaps something like this would work —
movhm = @(x) 2./movsum(1./x,2);
v = 1:5
v = 1×5
1 2 3 4 5
movhm(v)
ans = 1×5
2.0000 1.3333 2.4000 3.4286 4.4444
would work.
.

dpb on 3 Jul 2022
Edited: dpb on 4 Jul 2022
Simplest is probably just brute-force --
HM=[Kd_1(1) arrayfun(@(i)harmmean(Kd_1(i:i+1)),1:numel(Kd_1)-1) Kd_1(end)].';
##### 2 CommentsShowHide 1 older comment
dpb on 4 Jul 2022
Yeah, I made a local array of K=Kd_1(1:15) so wasn't too much to look at in command window...then didn't fix -- and arrayfun returns row vector didn't transpose...