separate rain events by specific dry period
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Albert Johan Mamani Larico
on 12 May 2022
Commented: Jovon Jacob
on 8 Jan 2023
Hi
I have hourly rain data for a period of 5 years
x = [0 0 0 0 0 2 4 5 14 10 16 0 0 0 0 0 24 33 22 0 0 2 3 5 0 0 0 0.........]
I need to group them considering that each rain event is separated by 3 hours of zero values or more
How could I get the numbers of rain events, their mean rain value and duration of each event?
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Accepted Answer
Image Analyst
on 12 May 2022
Try this, if you have the Image Processing Toolbox.
x = [0 0 0 0 0 2 4 5 14 10 16 0 0 0 0 0 24 33 22 0 0 2 3 5 0 0 0 0]
props = regionprops(x > 0, x, 'Area', 'MeanIntensity')
numberOfRainPeriods = length(props)
stormLengths = [props.Area] % In hours
meanRainPerHour = [props.MeanIntensity] % In mm or whatever.
integratedRainTotalsPerStorm = stormLengths .* meanRainPerHour % In mm or whatever.
You get
numberOfRainPeriods =
3
stormLengths =
6 3 3
meanRainPerHour =
8.5 26.333 3.3333
integratedRainTotalsPerStorm =
51 79 10
3 Comments
Image Analyst
on 7 Jan 2023
@Jovon Jacob give an example. Input, and output vectors. Best if you start your own thread and attach this code as your starting code.
Jovon Jacob
on 8 Jan 2023
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