hello sir, thanks for the reply.where I mentioned 46 i.e the data length of single site,similarly there are 7 sites and all are having different data length.how to incorporate that.
how to vary data length in the given code.There are 7 sites an each site having different data length.For example n1=18, n2=29 and so on N=number of sites are 7.
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for i=1:500
for j=1:7
b0(j,:,i)=D(j,:,i)/46;
for k=1:45
b1(j,k,i)=(D(j,k,i)*(46-k))/(46*45);
for m= 1:44
b2(j,m,i)=(D(j,m,i)*(46-m)*(46-m-1))/(46*45*44);
for n=1:43
b3(j,n,i)=(D(j,n,i)*(46-n)*(46-n-1)*(46-n-2))/(46*45*44*43);
end
end
end
end
end
6 Comments
dpb
on 6 May 2022
First, turn the calculation into a function that operates over the size of the inputs passed into it instead of hardcoding fixed limits for loops.
Then read in the data for each case into an array and call your function with it.
As noted above, the problem arises when you use hardcoded constants in the code instead of variables and also in not factoring out the code that does the same operations over each data set into a separate, callable function.
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