Check for incorrect argument data type or missing argument in call to function 'isfinite'.
1 view (last 30 days)
Show older comments
c=8;
x=9;
y=10;
f=@(x,y)(f1(x,y,c)+f3(x,y,c));
ff=@(x,y)f2(x,y,c);
eqs=@(x,y)[f(x,y),ff(x,y)];
sols=[0,0];
sols=fsolve(@(x,y)eqs,[2,1]);
function f=f1(x,y,c)
f=x*y-c;
end
function ff=f2(x,y,c)
ff=1-c*x/y;
end
function fff=f3(x,y,c)
fff=1;
end
Trying to learn how to use fsolve and stuck on this. Any help?
0 Comments
Answers (1)
Star Strider
on 1 May 2022
Change ‘eqs’ to be a funciton one one argument, and it works —
c=8;
x=9;
y=10;
f=@(x,y)(f1(x,y,c)+f3(x,y,c));
ff=@(x,y)f2(x,y,c);
eqs=@(b)[f(b(1),b(2)),ff(b(1),b(2))]; % <— Needs To Be Parameterised With One Vector Argument
sols=[0,0];
sols=fsolve(eqs,[2,1])
function f=f1(x,y,c)
f=x*y-c;
end
function ff=f2(x,y,c)
ff=1-c*x/y;
end
function fff=f3(x,y,c)
fff=1;
end
.
0 Comments
See Also
Categories
Find more on Logical in Help Center and File Exchange
Products
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!